如图直线AB，cD相交于点o，OE丄oF，oc平分角AoE，且角BoF=2角B0B，角BoD=?

∵OE⊥OF
∴角EOF=90°

∵角BOF=2角BOE

∴2角BOE+角BOE=90°

∴角BOE=30°
∵角AOB=180°

∴角AOE=角AOB-角BOE=180°-30°=150°

∵OC平分角AOE

∴角AOC=1/2角AOE=75°

∵角BOD与角AOC是对顶角
∴角BOD=角AOC=75°