1.A chromophore solution is places in a 1 × 1 cm regular fluorescence cuvette. The absorbance of this solution, at 1 cm path length, is 0.80 at 450 nm and 0.30 at 530 nm. When the sample is excited at 450 nm and the fluorescence emission... 1.A chromophore solution is places in a 1 × 1 cm regular fluorescence cuvette. The absorbance of this
solution, at 1 cm path length, is 0.80 at 450 nm and 0.30 at 530 nm. When the sample is excited at 450
nm and the fluorescence emission is measured at 530 nm (both were set at a very narrow 5 nm slit for
spectral band width), the observed fluorescence emission is 100 arbitrary unit. Calculate the theoretical
fluorescence emission intensity (using the same arbitrary unit) after corrections for the inner filter effects
on both excitation and emission. Show critical steps of calculation.
2.
For a particular Donor:Acceptor pair, the spectral overlap integral “J” between the corrected donor
fluorescence emission and the acceptor absorption is
1.58 x10-13 (cm3 M-1) and the efficiency of
fluorescence energy transfer is 0.667. Assuming 2/3 for the dipole orientation factor κ2 and 1.4 for therefractive index “n” of the medium, calculate the value of R. Show critical steps of calculation.